4[(8-y)+2(y-1)]=2

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Solution for 4[(8-y)+2(y-1)]=2 equation:


Simplifying
4[(8 + -1y) + 2(y + -1)] = 2

Remove parenthesis around (8 + -1y)
4[8 + -1y + 2(y + -1)] = 2

Reorder the terms:
4[8 + -1y + 2(-1 + y)] = 2
4[8 + -1y + (-1 * 2 + y * 2)] = 2
4[8 + -1y + (-2 + 2y)] = 2

Reorder the terms:
4[8 + -2 + -1y + 2y] = 2

Combine like terms: 8 + -2 = 6
4[6 + -1y + 2y] = 2

Combine like terms: -1y + 2y = 1y
4[6 + 1y] = 2
[6 * 4 + 1y * 4] = 2
[24 + 4y] = 2

Solving
24 + 4y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-24' to each side of the equation.
24 + -24 + 4y = 2 + -24

Combine like terms: 24 + -24 = 0
0 + 4y = 2 + -24
4y = 2 + -24

Combine like terms: 2 + -24 = -22
4y = -22

Divide each side by '4'.
y = -5.5

Simplifying
y = -5.5

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